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Find the product: (a − 1/a)⁢(a^2 + 1/a^2 + 1) - Mathematics

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प्रश्न

Find the product:

`(a - 1/a)(a^2 + 1/a^2 + 1)`

योग
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उत्तर

Given: `(a - 1/a)(a^2 + 1/a^2 + 1)`

Stepwise calculation:

1. Expand the product: 

`(a - 1/a)(a^2 + 1/a^2 + 1)`

= `a(a^2 + 1/a^2 + 1) - 1/a(a^2 + 1/a^2 + 1)`

2. Multiply terms inside:

= `(a^3 + a xx 1/a^2 + a) - (a^2/a + 1/a xx 1/a^2 + 1/a)`

3. Simplify powers:

= (a3 + a–1 + a) – (a1 + a–3 + a–1)

4. Group like terms:

= a3 + a–1 + a – a – a–3 – a–1

5. Cancel terms (a) and (a–1):

= a3 – a–3

So, the product `(a - 1/a)(a^2 + 1/a^2 + 1) = a^3 - 1/a^3`.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Expansions - Exercise 3A [पृष्ठ ६४]

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नूतन Mathematics [English] Class 9 ICSE
अध्याय 3 Expansions
Exercise 3A | Q 12. (ii) | पृष्ठ ६४
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