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प्रश्न
Find the product:
`(a - 1/a)(a^2 + 1/a^2 + 1)`
योग
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उत्तर
Given: `(a - 1/a)(a^2 + 1/a^2 + 1)`
Stepwise calculation:
1. Expand the product:
`(a - 1/a)(a^2 + 1/a^2 + 1)`
= `a(a^2 + 1/a^2 + 1) - 1/a(a^2 + 1/a^2 + 1)`
2. Multiply terms inside:
= `(a^3 + a xx 1/a^2 + a) - (a^2/a + 1/a xx 1/a^2 + 1/a)`
3. Simplify powers:
= (a3 + a–1 + a) – (a1 + a–3 + a–1)
4. Group like terms:
= a3 + a–1 + a – a – a–3 – a–1
5. Cancel terms (a) and (a–1):
= a3 – a–3
So, the product `(a - 1/a)(a^2 + 1/a^2 + 1) = a^3 - 1/a^3`.
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Expansions - Exercise 3A [पृष्ठ ६४]
