Advertisements
Advertisements
प्रश्न
Find the point on the y-axis which is equidistant from the points (S, - 2) and (- 3, 2).
Advertisements
उत्तर
Since the point is on y-axis so, X - coordinate is zero
Let the point be (0, y)
It's distance from A{5, - 2) and B(-3, 2) are equal
∴ `sqrt((0 - 5)^2 +( y+2)^2) = sqrt((0+3)^2 +(y - 2)^2)`
⇒ 25 + Y2 + 4y + 4 = 9 + y2 - 4y+4 [squaring both sides]
⇒ 4y + 29= -4y + 13
⇒ 4y+ 4y=13-29
⇒ 8y = - 16 ∴y =`(-16)/8` = -2
Thus ,the point is (0, -2).
APPEARS IN
संबंधित प्रश्न
Name the quadrilateral formed, if any, by the following points, and given reasons for your answers:
A(-1,-2) B(1, 0), C (-1, 2), D(-3, 0)
Find the ratio in which the line segment joining (-2, -3) and (5, 6) is divided by x-axis Also, find the coordinates of the point of division in each case.
If the point A (4,3) and B ( x,5) lies on a circle with the centre o (2,3) . Find the value of x.
Find the area of a quadrilateral ABCD whose vertices area A(3, -1), B(9, -5) C(14, 0) and D(9, 19).
Find the area of the triangle formed by joining the midpoints of the sides of the triangle whose vertices are A(2,1) B(4,3) and C(2,5)
If the points A (1,2) , O (0,0) and C (a,b) are collinear , then find a : b.
If A (2, 2), B (−4, −4) and C (5, −8) are the vertices of a triangle, than the length of the median through vertex C is
If points (t, 2t), (−2, 6) and (3, 1) are collinear, then t =
The line 3x + y – 9 = 0 divides the line joining the points (1, 3) and (2, 7) internally in the ratio ______.
Points (1, –1) and (–1, 1) lie in the same quadrant.
