Advertisements
Advertisements
प्रश्न
Find the coordinates of point A, where AB is a diameter of the circle with centre (–2, 2) and B is the point with coordinates (3, 4).
Advertisements
उत्तर
Let the centre of the circle be O.
Since AB is the diameter so, O is the midpoint of AB.
Thus, using the section formula,
`(a+3)/(2) = - 2`
⇒ `a = -4 - 3 = -7`
And
`(b + 4)/(2) = 2`
⇒ `b = 4 - 4 = 0`
So, the coordinate of point A is (-7,0).
APPEARS IN
संबंधित प्रश्न
Let ABCD be a square of side 2a. Find the coordinates of the vertices of this square when The centre of the square is at the origin and coordinate axes are parallel to the sides AB and AD respectively.
Find the distance between the following pair of points:
(a, 0) and (0, b)
Two vertices of an isosceles triangle are (2, 0) and (2, 5). Find the third vertex if the length of the equal sides is 3.
Which point on the y-axis is equidistant from (2, 3) and (−4, 1)?
A (3, 2) and B (−2, 1) are two vertices of a triangle ABC whose centroid G has the coordinates `(5/3,-1/3)`Find the coordinates of the third vertex C of the triangle.
Find the ratio in which the point P(m, 6) divides the join of A(-4, 3) and B(2, 8) Also, find the value of m.
Points A(-1, y) and B(5,7) lie on the circle with centre O(2, -3y).Find the value of y.
The ordinate of any point on x-axis is
If points A (5, p) B (1, 5), C (2, 1) and D (6, 2) form a square ABCD, then p =
Points (1, –1) and (–1, 1) lie in the same quadrant.
