Advertisements
Advertisements
प्रश्न
Find the coordinates of point A, where AB is a diameter of the circle with centre (–2, 2) and B is the point with coordinates (3, 4).
Advertisements
उत्तर
Let the centre of the circle be O.
Since AB is the diameter so, O is the midpoint of AB.
Thus, using the section formula,
`(a+3)/(2) = - 2`
⇒ `a = -4 - 3 = -7`
And
`(b + 4)/(2) = 2`
⇒ `b = 4 - 4 = 0`
So, the coordinate of point A is (-7,0).
APPEARS IN
संबंधित प्रश्न
Show that the points A (1, 0), B (5, 3), C (2, 7) and D (−2, 4) are the vertices of a parallelogram.
If the point A (4,3) and B ( x,5) lies on a circle with the centre o (2,3) . Find the value of x.
Find the value of a, so that the point ( 3,a ) lies on the line represented by 2x - 3y =5 .
Find the coordinates of the points of trisection of the line segment joining the points (3, –2) and (–3, –4) ?
Find the coordinates of the centre of the circle passing through the points P(6, –6), Q(3, –7) and R (3, 3).
Points (−4, 0) and (7, 0) lie
Find the area of triangle with vertices ( a, b+c) , (b, c+a) and (c, a+b).
The ratio in which the x-axis divides the segment joining (3, 6) and (12, −3) is
If (−2, 1) is the centroid of the triangle having its vertices at (x , 0) (5, −2), (−8, y), then x, y satisfy the relation
Abscissa of a point is positive in ______.
