Question

Find the coordinates of point A, where AB is a diameter of the circle with centre (–2, 2) and B is the point with coordinates (3, 4).

Answer 1

 

Let the centre of the circle be O. 
Since AB is the diameter so, O is the midpoint of AB.
Thus, using the section formula,

`(a+3)/(2) = - 2`

⇒ `a = -4 - 3 = -7`

And

`(b + 4)/(2) = 2`

⇒ `b = 4 - 4 = 0`

So, the coordinate of point A is (-7,0).