Question

Find the perimeter and area of the figure given below. `(pi = 22/7)`

Answer 1

Perimeter = sum of outside lengths

Length of the arc of quadrant circle = `1/4 xx 2pi"r units"`

= `1/2 xx 22/7 xx 3.5  "cm"`

= 11 × 0.5 cm = 5.5 cm

∴ Length of arc of 2 sectors 2 × 5.5 cm

= 11 cm

∴ Perimeter P = 11 + 6 + 3.5 + 6 + 35 cm

P = 30 cm

Area Area of 2 quadrant circle + Area of a rectangle.

= `2 xx 1/4pi"r"^2 + "lb"  "sq.units"`

= `(1/2 xx 22/7 xx 3.5 xx 3.5) + (6 xx 3.5)  "cm"^2`

= (11 × 3.5 × 0.5) + 21 cm²

= (19.25 + 21) cm² = 40.25 cm²

∴ Area = 40.25 cm² (approx)