Advertisements
Advertisements
प्रश्न
Find the number of sides in a regular polygon, if its interior angle is equal to its exterior angle.
Advertisements
उत्तर
Let each exterior angle or interior angle be = x°
∴ x + x = 180°
2x = 180°
x = 90°
Now, let no. of sides = n
∵ each exterior angle = `360^circ/"n"`
∴ 90° = `360^circ/"n"`
n = `360^circ/90^circ`
n = 4
APPEARS IN
संबंधित प्रश्न
Find the number of sides in a regular polygon, if its interior angle is: 135°
Find the number of sides in a regular polygon, if its exterior angle is : `1/3` of right angle
Find the number of sides in a regular polygon, if its exterior angle is: two-fifth of right angle
Two alternate sides of a regular polygon, when produced, meet at the right angle. Calculate the number of sides in the polygon.
In a regular pentagon ABCDE, draw a diagonal BE and then find the measure of:
(i) ∠BAE
(ii) ∠ABE
(iii) ∠BED
If the difference between the exterior angle of a 'n' sided regular polygon and an (n + 1) sided regular polygon is 12°, find the value of n.
Calculate the number of sides of a regular polygon, if: its interior angle is five times its exterior angle.
Find a number of side in a regular polygon, if it exterior angle is: 30°.
Find number of side in a regular polygon, if it exterior angle is: 36
Is it possible to have a regular polygon whose interior angle is: 155°
