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Find the nth derivative of the following : cos x - Mathematics and Statistics

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प्रश्न

Find the nth derivative of the following : cos x

योग
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उत्तर

Let y = cos x

Then `"dy"/"dx" = "d"/"dx"(cosx)`
= `-sinx`
= `cos(pi/2 + x)`

`(d^2y)/(dx^2) = "d"/"dx"(-sinx)`
= `-cosx`
= cos(π + x)

= `cos((2pi)/2 + x)`

`(d^3y)/(dx^3) = "d"/"dx"(-cosx)`

= `-"d"/"dx"(cosx)`
= – ( – sin x)
= sin x

= `cos((3pi)/2 + x)`
In general, the nth order derivative is given by
`(d^ny)/(dx^n) = cos((npi)/2 + x)`.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Differentiation - Exercise 1.5 [पृष्ठ ६०]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.5 | Q 4.06 | पृष्ठ ६०

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