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Differentiate cos-1(1-x21+x2)w.r.t.tan-1x. - Mathematics and Statistics

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प्रश्न

Differentiate `cos^-1((1 - x^2)/(1 + x^2)) w.r.t. tan^-1 x.`

योग
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उत्तर

Let u = `cos^-1((1 - x^2)/(1 + x^2)) and v = tan^-1x`.

Then we want to find `"du"/"dv"`.
Put x = tanθ.
Then = tan–1 x.
∴ u = `cos^-1((1 - tan^2θ)/(1 + tan^2θ))`
= cos–1(cos2θ)
= 2θ
∴ u = 2tan–1x
∴ `"du"/"dx" = 2."d"/"dx"(tan^-1x)`

= `2 xx (1)/(1 + x^2)`

= `(2)/(1 + x^2)`
Also, v =tan–1x
∴ `"dv"/"dx" = "d"/"dx"(tan^-1x) =  (1)/(1 + x^2)`

∴ `"du"/"dv" = (("dy"/"dx"))/(("dv"/"dx")`

= `(((2)/(1 + x^2)))/(((1)/(1 + x^2))`
= 2.

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अध्याय 1: Differentiation - Exercise 1.4 [पृष्ठ ४९]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.4 | Q 4.4 | पृष्ठ ४९

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