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Find the nth derivative of the following : apx+q - Mathematics and Statistics

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प्रश्न

Find the nth derivative of the following : apx+q 

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उत्तर

Let y = apx+q 

Then `"dy"/"dx" = "d"/"dx"(a^(px + q))`

= `a^(px + q)loga."d"/"dx"(px + q)`

`(d^2y)/(dx^2) = "d"/"dx"[ploga.a^(px + q)]`

= `ploga."d"/"dx"(a^(px + q))`

= `ploga.a^(px + q).log a."d"/"dx"(px + q)`

= `ploga.a^(px + q).log a xx (p xx 1 + 0)`

= `p^2.(loga)^2.a^(px + q)`

`(d^3y)/(dx^3) = "d"/"dx"[p^2.(loga)^2.a^(px + q)]`

= `p^2.(loga)^2."d"/"dx"(a^(px + q))`

= `p^2.(log a)^2.a^(px + q).log a."d"/"dx"(px + q)`

= `p^2.(loga)^3.a^(px + q) xx (p xx 1 + 0)`

= `p^3.(loga)^3.a^(px + q)`
In general, the nth order derivative is given by
`(d^ny)/(dx^n) = p^n.(loga)^n.a^(px + q)`.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Differentiation - Exercise 1.5 [पृष्ठ ६०]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.5 | Q 4.04 | पृष्ठ ६०

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