Question

Find the least number which when divided by 25, 40, and 60 leaves 9 as the remainder in each case.

Answer 1

25, 40, and 60 exactly divides the least number that is equal to their LCM.
So, the required number that leaves 9 as a remainder will be LCM + 9.
Finding the LCM:

LCM = 2³ × 3 × 5² = 600
∴ Required number = 600 + 9 = 609