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Find the integrals of the function: sin 3x cos 4x

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प्रश्न

Find the integrals of the function:

sin 3x cos 4x

योग
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उत्तर

Let `I = int sin 3x cos  4 x dx`

`1/2 int [sin (3x + 4x) + sin (3x - 4x)] dx`     ...[∵ 2 sin A cos B =  sin (A + B) + sin (A - B)]

`= 1/2 int [sin 7 x + sin (-x)] dx`

`= 1/2 int (sin 7x - sin x) dx`

`= 1/2 ((-cos 7x)/7) - 1/2 (-cos x) + C`

`= -1/14 cos 7x + 1/2 cos x + C`

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अध्याय 7: Integrals - Exercise 7.3 [पृष्ठ ३०७]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.3 | Q 2 | पृष्ठ ३०७

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