Advertisements
Advertisements
प्रश्न
Find `int (sin^2 x - cos^2x)/(sin x cos x) dx`
Advertisements
उत्तर
`int (sin^2 x - cos^2x)/(sin x cos x) dx`
= `int (sin^2 x)/(sin x cos x) dx - int (cos^2 x)/(sin x cos x) dx`
= `int tan x dx - int cot x dx`
= log |sec x| - log |sin x| + C
APPEARS IN
संबंधित प्रश्न
Evaluate : `intsin(x-a)/sin(x+a)dx`
Find the integrals of the function:
sin3 x cos3 x
Find the integrals of the function:
sin 4x sin 8x
Find the integrals of the function:
`cos x/(1 + cos x)`
Find the integrals of the function:
`(cos x - sinx)/(1+sin 2x)`
Find the integrals of the function:
tan3 2x sec 2x
Find the integrals of the function:
tan4x
Find the integrals of the function:
`(sin^3 x + cos^3 x)/(sin^2x cos^2 x)`
Find the integrals of the function:
`(cos 2x+ 2sin^2x)/(cos^2 x)`
Find the integrals of the function:
`1/(cos(x - a) cos(x - b))`
`int (e^x(1 +x))/cos^2(e^x x) dx` equals ______.
Find `int dx/(x^2 + 4x + 8)`
Evaluate `int_0^(3/2) |x sin pix|dx`
Find `int (2x)/((x^2 + 1)(x^4 + 4))`dx
Find `int_ (sin "x" - cos "x" )/sqrt(1 + sin 2"x") d"x", 0 < "x" < π / 2 `
Find `int_ (log "x")^2 d"x"`
Integrate the function `cos("x + a")/sin("x + b")` w.r.t. x.
`int "dx"/(sin^2x cos^2x)` is equal to ______.
Evaluate the following:
`int sqrt(1 + sinx)"d"x`
Evaluate the following:
`int (sin^6x + cos^6x)/(sin^2x cos^2x) "d"x`
Evaluate the following:
`int (cosx - cos2x)/(1 - cosx) "d"x`
The value of the integral `int_(1/3)^1 (x - x^3)^(1/3)/x^4 dx` is
What does integration using trigonometric identities mean?
Which identity is used for an even power of cosine?
Which identity is used for the product of sine and cosine?
What is \(\int \cos^2 x\,dx\)?
What is \(\int \sin 2x\cos 3x\,dx\)?
What must always be added to an indefinite integral?
