Advertisements
Advertisements
प्रश्न
Find the fourth proportional to 2xy, x2 and y2.
Advertisements
उत्तर
Let the fourth proportional to 2xy, x2 and y2 be n.
`=> 2xy : x^2 = y^2 : n`
`=> 2xy xx n = x^2 xx y^2`
`=> n = (x^2y^2)/(2xy) = (xy)/2`
APPEARS IN
संबंधित प्रश्न
What least number must be added to each of the numbers 6, 15, 20 and 43 to make them proportional?
If x, y, z are in continued proportion, prove that `(x + y)^2/(y + z)^2 = x/z`
Find the mean proportional of the following:
17.5, 0.007
Find the mean proportion of the following :
0.09 and 0.25
If q is the mean proportional between p and r, prove that
`p^2 - q^2 + r^2 = q^4[(1)/p^2 - (1)/q^2 + (1)/r^2]`.
Find the third proportional to `5(1)/(4) and 7.`
In an army camp, there were provisions for 550 men for 28 days. But, 700 men attended the camp. How long did the provisions last?
If a, b, c are in continued proportion, prove that: (a + b + c) (a – b + c) = a2 + b2 + c2
Determine if the following are in proportion.
33, 44, 75, 100
Determine if the following ratios form a proportion. Also, write the middle terms and extreme terms where the ratios form a proportion.
2 kg : 80 kg and 25 g : 625 g
