Question

Find the equation of the line, whose x-intercept = 5 and y-intercept = 3

Answer 1

When x-intercept = 5, corresponding point on x-axis is (5, 0)

When y-intercept = 3, corresponding point on y-axis is (0, 3).

Let (x₁, y₁) = (5, 0) and (x₂, y₂) = (0, 3)

Slope = `(3 - 0)/(0 - 5) = (-3)/5`

The required equation is:

y – y₁ = m(x – x₁)

`y - 0 = (-3)/5(x - 5)`

5y = –3x + 15

3x + 5y = 15