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Find the direction cosines of a vector whose direction ratios are 12,12,12 - Mathematics

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प्रश्न

Find the direction cosines of a vector whose direction ratios are

`1/sqrt(2), 1/2, 1/2`

योग
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उत्तर

The given direction ratios are a = 3, b = – 1 , c = 3

If a, b, c are the direction ratios of a vector ten the direction cosines of the vector are

l = `"b"/sqrt("a"^2 + "b"^2 + "c"^2)`

m = `"b"/sqrt("a"^2 + "b"^2 + "c")`

c = `"c"/sqrt("a"^2 + "b"^2 + "c")`

∴ The required direction cosioes of the water are

`3/sqrt(3^2 + (-1)^2 + 3^2)`

`(-1)/sqrt(3^2 + (-1)^2 + 3^2)`

`3/sqrt(3^2 + (-1)^2 + 3^2)`

`3/sqrt(9 + 1 + 9)`

`(- 1)/sqrt(9 + 1 + 9)`

`3/sqrt(9 + 1 + 9)`

`(3/sqrt(19), (-1)/sqrt(9 + 1+ 9))`

`3/sqrt(9 + 1 + 9)`

`1/sqrt(19), (-1)/sqrt(19)`

= `3sqrt(9 + 1 + 9)`

`(3/sqrt(19), (-1) /sqrt(19), 3/sqrt(19))`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Vector Algebra - Exercise 8.2 [पृष्ठ ६०]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 8 Vector Algebra
Exercise 8.2 | Q 2. (ii) | पृष्ठ ६०

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