Advertisements
Advertisements
प्रश्न
Find the degree of (2a2 + 3ab – b2) – (3a2 – ab – 3b2)
Advertisements
उत्तर
(2a2 + 3ab – b2) – (3a2 – ab – 3b2)
= (2a2 + 3ab – b2) + (– 3a2 + ab + 3b2)
= 2a2 + 3ab – b2 – 3a2 + ab + 3b2
= 2a2 – 3a2 + 3ab + ab + 3b2 – b2
= 2a2 – 3a2 + ab(3 + 1) + b2(3 – 1)
= – a2 + 4ab + 2b2
Hence degree of the expression is 2.
APPEARS IN
संबंधित प्रश्न
Any integer can be the degree of the expression
Find the degree of the following terms.
5x2
Find the degree of the following terms.
−7ab
Find the degree of the following terms.
12pq2r2
Find the degree of the following expression.
x3 – 1
Find the degree of the following expression.
3t4 – 5st2 + 7s2t2
Find the degree of the following expression.
u5 + u4v + u3v2 + u2v3 + uv4
Add and find the degree of the following expressions.
(9x + 3y) and (10x – 9y)
Simplify and find the degree of 6x2 + 1 – [8x – {3x2 – 7 – (4x2 – 2x + 5x + 9)}]
The two adjacent sides of a rectangle are 2x2 – 5xy + 3z2 and 4xy – x2 – z2. Find the perimeter and the degree of the expression
