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सी.आई.एस.सी.ई.आईसीएसई ICSE Class 8

Find the Cube-root of 1728.

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प्रश्न

Find the cube-root of 1728.

योग
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उत्तर

1728
= `root(3)(1728)`
= (2 x 2 x 2) x (2 x 2 x 2) x (3 x 3 x 3)
= 2 x 2 x 3
=12

2 1728
2 864
2 432
2 216
2 108
2 54
3 27
3 9
3 3
  1
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अध्याय 4: Cubes and Cube Roots - Exercise 4 (B) [पृष्ठ ५१]

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सेलिना Concise Mathematics [English] Class 8 ICSE
अध्याय 4 Cubes and Cube Roots
Exercise 4 (B) | Q 1.4 | पृष्ठ ५१

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