Advertisements
Advertisements
प्रश्न
Find the compound ratio of `sqrt(2) : 1, 3: sqrt(5)` and `sqrt(20) : 9`
Advertisements
उत्तर
Required compound ratio = `sqrt(2) xx 3 xx sqrt(20) : 1 xx sqrt(5) xx 9`
= `(sqrt(2) xx 3 xx sqrt(20))/(1 xx sqrt(5) xx 9)`
= `(sqrt(2) xx sqrt(4))/3`
= `(2sqrt(2))/3`
= `2sqrt(2) : 3`
APPEARS IN
संबंधित प्रश्न
If 2a = 3b and 4b = 5c, find: a : c.
Find the duplicate ratio of the following :
`sqrt 10 : sqrt 14`
Divide Rs. 720 between Sunil, Sbhil and Akhil. So that Sunil gets 4/5 of Sohil’s and Akhil’s share together and Sohil gets 2/3 of Akhil’s share.
The ratio between two numbers is 3: 4. If their L.C.M., is 180. Find the numbers.
If (a – x) : (b – x) be the duplicate ratio of a: b show that:
`(1)/x = (1)/a + (1)/b.`
Two numbers are in the ratio 4 : 7. If their L.C.M. is 168, find the numbers.
If y (3x – y) : x (4x + y) = 5 : 12. Find (x² + y²) : (x + y)².
Out of 50 students in a class, 30 are boys. Find the ratio of number of girls to the total number of students
The ratio of the area of the shaded portion to that of the whole figure is ______.
Length and breadth of the floor of a room are 5 m and 3 m, respectively. forty tiles, each with area `1/16` m2 are used to cover the floor partially. Find the ratio of the tiled and the non tiled portion of the floor.
