Advertisements
Advertisements
प्रश्न
Find the sub-triplicate ratio of the following :
`(64 "m"^3)/(729 "n"^3) : (216 "m"^3)/(27"n"^3)`
Advertisements
उत्तर
`(64 "m"^3)/(729 "n"^3) : (216 "m"^3)/(27"n"^3)`
`= ((64 "m"^3)/(729 "n"^3))^(1/3) : ((216 "m"^3)/(27"n"^3))^(1/3)`
`= (4"m")/(9"n") : (6"m")/(3"n")`
`= (4"m")/(9"n") xx (6"m")/(3"n")`
`= 2/9`
Sub-triplicate raoo = 2 : 9
APPEARS IN
संबंधित प्रश्न
The 4th term of a G.P. is 16 and the 7th term is 128. Find the first term and common ratio of the series
Divide Rs. 1290 in to A, B and C such that A is `2/5` of B and B : C = 4 : 3.
If m : n is the duplicate ratio of m + x : n + x; show that x2 = mn.
Convert the following percentage to fractions and ratio:
0.25%
If p + r = 2q and `(1)/q + (1)/s = (2)/r`, then prove that p : q = r : s.
Express the given ratio in its simplest form: 10 paise : ₹ 1
If P : Q = `1/2 : 1/3` and Q : R = `1 1/2 : 1 1/3`, find P : R.
A rail journey of 75 km costs Rs 215. How much will a journey of 120 km cost?
The length and breadth of a window are in 1m and 70 cm respectively. The ratio of the length to the breadth is _______________
A ratio expressed in lowest form has no common factor other than ______ in its terms.
