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Find the Squares of the Following Numbers Using Column Method. Verify the Result by Finding the Square Using the Usual Multiplication: 54

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प्रश्न

Find the squares of the following numbers using column method. Verify the result by finding the square using the usual multiplication: 

 54 

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उत्तर

Here, a = 5, b = 4
Step 1. Make 3 columns and write the values of a2, 2 x a x b and b2 in these columns.

Column I Column II Column III
a2 2 x a x b b2
25 40 16

Step 2. Underline the unit digit of b2 (in Column III) and add its tens digit, if any, with 2 x a x b (in Column II).

Column I Column II Column III
a2 2 x a x b b2
25 40 + 1 16
  41  

Step 3. Underline the unit digit in Column II and add the number formed by the tens and other digits, if any, with a2 in Column I.

Column I Column II Column III
a2 2 x a x b b2
25 + 4 40 + 1 16
29 41  

Step 4. Underline the number in Column I.

Column I Column II Column III
a2 2 x a x b b2
25 + 4 40 + 1 16
29 41  

Step 5. Write the underlined digits at the bottom of each column to obtain the square of the given number.
In this case, we have:
542 = 2916
Using multiplication:
    54
    54
  216
270  
2916
This matches with the result obtained using the column method.

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अध्याय 3: Squares and Square Roots - Exercise 3.3 [पृष्ठ ३२]

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आर.डी. शर्मा Mathematics [English] Class 8
अध्याय 3 Squares and Square Roots
Exercise 3.3 | Q 1.3 | पृष्ठ ३२

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Observe the following pattern 

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\[ 1 + 2 = \frac{1}{2}\left\{ 2 \times \left( 2 + 1 \right) \right\}\]
\[ 1 + 2 + 3 = \frac{1}{2}\left\{ 3 \times \left( 3 + 1 \right) \right\}\]
\[1 + 2 + 3 + 4 = \frac{1}{2}\left\{ 4 \times \left( 4 + 1 \right) \right\}\]and find the values of following:

31 + 32 + ... + 50


Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :  

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