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Find the Shortest Distance Between the Following Pairs of Lines Whose Vector Are: → R = ( 3 ^ I + 5 ^ J + 7 ^ K ) + λ ( ^ I − 2 ^ J + 7 ^ K ) and → R = − ^ I − ^ J − ^ K + μ ( 7 ^ I − 6 ^ J + ^ K )

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प्रश्न

Find the shortest distance between the following pairs of lines whose vector equations are: \[\overrightarrow{r} = \left( 3 \hat{i} + 5 \hat{j} + 7 \hat{k} \right) + \lambda\left( \hat{i} - 2 \hat{j} + 7 \hat{k} \right) \text{ and } \overrightarrow{r} = - \hat{i} - \hat{j} - \hat{k}  + \mu\left( 7 \hat{i}  - 6 \hat{j}  + \hat{k}  \right)\]

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उत्तर

\[\overrightarrow{r} = \left( 3 \hat{i} + 5 \hat{j} + 7 \hat{k} \right) + \lambda\left( \hat{i} - 2 \hat{j} + 7 \hat{k}  \right) \text{ and }  \overrightarrow{r} = - \hat{i} - \hat{j} - \hat{k} + \mu\left( 7 \hat{i} - 6 \hat{j} + \hat{k} \right)\]

Comparing the given equations with the equations 

\[\overrightarrow{r} = \overrightarrow{a_1} + \lambda \overrightarrow{b_1} \text{ and } \overrightarrow{r} = \overrightarrow{a_2} + \mu \overrightarrow{b_2}\] ,

we get , 

\[\overrightarrow{a_1} = 3 \hat{i} + 5 \hat{j} + 7 \hat{k} \]

\[ \overrightarrow{a_2} = - \hat{i} - \hat{j} - \hat{k} \]

\[ \overrightarrow{b_1} = \hat{i} - 2 \hat{j} + 7 \hat{k} \]

\[ \overrightarrow{b_2} = 7 \hat{i} - 6 \hat{j} + \hat{k} \]

\[ \therefore \overrightarrow{a_2} - \overrightarrow{a_1} = - 4 \hat{i} - 6 \hat{j} - 8 \hat{k} \]

\[\text { and }\overrightarrow{b_1} \times \overrightarrow{b_2} = \begin{vmatrix}\hat{i} & \hat{j} & \hat{k} \\ 1 & - 2 & 7 \\ 7 & - 6 & 1\end{vmatrix}\]

\[ = 40 \hat{i} + 48 \hat{j} + 8 \hat{k} \]

\[ \Rightarrow \left| \overrightarrow{b_1} \times \overrightarrow{b_2} \right| = \sqrt{{40}^2 + {48}^2 + 8^2}\]

\[ = \sqrt{1600 + 2304 + 64}\]

\[ = \sqrt{3968}\]

\[\left( \overrightarrow{a_2} - \overrightarrow{a_1} \right) . \left( \overrightarrow{b_1} \times \overrightarrow{b_2} \right) = \left( - 4 \hat{i} - 6 \hat{j} - 8 \hat{k}  \right) . \left( 40 \hat{i} + 48 \hat{j} + 8 \hat{k}  \right)\]

\[ = - 160 - 288 - 64\]

\[ = - 512\]

The shortest distance between the lines , 

\[\overrightarrow{r} = \overrightarrow{a_1} + \lambda \overrightarrow{b_1} \text{ and } \overrightarrow{r} = \overrightarrow{a_2} + \mu \overrightarrow{b_2}\] is given by 

\[d = \left| \frac{\left( \overrightarrow{a_2} - \overrightarrow{a_1} \right) . \left( \overrightarrow{b_1} \times \overrightarrow{b_2} \right)}{\left| \overrightarrow{b_1} \times \overrightarrow{b_2} \right|} \right|\]

\[ = \left| \frac{- 512}{\sqrt{3968}} \right|\]

\[ = \frac{512}{\sqrt{3968}}\] 

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अध्याय 27: Straight Line in Space - Exercise 28.5 [पृष्ठ ३७]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 27 Straight Line in Space
Exercise 28.5 | Q 1.2 | पृष्ठ ३७

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