Advertisements
Advertisements
प्रश्न
Find second and third terms of an A.P. whose first term is – 2 and the common difference is – 2.
Advertisements
उत्तर
a = t1 = – 2, d = – 2
∴ t2 = t1 + d = – 2 – 2 = – 4
t3 = t2 + d = – 4 – 2 = – 6
APPEARS IN
संबंधित प्रश्न
Find the sum of the following APs:
`1/15, 1/12, 1/10`, ... to 11 terms.
In an AP Given a12 = 37, d = 3, find a and S12.
Three numbers are in A.P. If the sum of these numbers is 27 and the product 648, find the numbers.
Find the sum of all integers between 100 and 550, which are divisible by 9.
If the 10th term of an AP is 52 and 17th term is 20 more than its 13th term, find the AP.
The 7th term of an AP is –4 and its 13th term is –16. Find the AP.
If (2p – 1), 7, 3p are in AP, find the value of p.
Two A.P.’s are given 9, 7, 5, ... and 24, 21, 18, ... If nth term of both the progressions are equal then find the value of n and nth term.
The first term of an A. P. is 5 and the common difference is 4. Complete the following activity and find the sum of the first 12 terms of the A. P.
a = 5, d = 4, s12 = ?
`s_n = n/2 [ square ]`
`s_12 = 12/2 [10 +square]`
`= 6 × square `
` =square`
For what value of p are 2p + 1, 13, 5p – 3 are three consecutive terms of an A.P.?
The first and last terms of an A.P. are 1 and 11. If the sum of its terms is 36, then the number of terms will be
If \[\frac{1}{x + 2}, \frac{1}{x + 3}, \frac{1}{x + 5}\] are in A.P. Then, x =
If \[\frac{5 + 9 + 13 + . . . \text{ to n terms} }{7 + 9 + 11 + . . . \text{ to (n + 1) terms}} = \frac{17}{16},\] then n =
The common difference of the A.P. \[\frac{1}{2b}, \frac{1 - 6b}{2b}, \frac{1 - 12b}{2b}, . . .\] is
In an A.P. (with usual notations) : given d = 5, S9 = 75, find a and a9
Shubhankar invested in a national savings certificate scheme. In the first year he invested ₹ 500, in the second year ₹ 700, in the third year ₹ 900 and so on. Find the total amount that he invested in 12 years.
Find the sum:
`(a - b)/(a + b) + (3a - 2b)/(a + b) + (5a - 3b)/(a + b) +` ... to 11 terms
Find the sum of last ten terms of the AP: 8, 10, 12,.., 126.
The sum of 41 terms of an A.P. with middle term 40 is ______.
Find the sum \[2 + 4 + 6 + \cdots + 20\] using the sum of the first n even natural numbers.
