Advertisements
Advertisements
प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by 5 + 2x .
Advertisements
उत्तर
Let us denote the given polynomials as
`f(x) = x^3 + 3x^2 + 3x + 1`
`k(x) = 5+2x`
`⇒ k(x) = 2 {x-(-5/2)}`
We will find the remainder when f(x)is divided by k(x).
By the remainder theorem, when f(x)is divided by k(x) the remainder is
`= f(-5/2)`
` = (-5/2)^3 + 3(-5/2)^2 + 3 (-5/2)+1`
`= 125/8 + 75/4 - 15/2` + 1
` = - 27/8`
APPEARS IN
संबंधित प्रश्न
If the polynomials ax3 + 3x2 − 13 and 2x3 − 5x + a, when divided by (x − 2) leave the same remainder, find the value of a.
f(x) = x3 − 6x2 + 11x − 6, g(x) = x2 − 3x + 2
Find the values of a and b, if x2 − 4 is a factor of ax4 + 2x3 − 3x2 + bx − 4.
x3 + 2x2 − x − 2
x3 − 6x2 + 3x + 10
2y3 − 5y2 − 19y + 42
x3 − 3x2 − 9x − 5
If both x − 2 and \[x - \frac{1}{2}\] are factors of px2 + 5x + r, then
Factorise the following:
6x2 + 16xy + 8y2
Factorise the following:
(p – q)2 – 6(p – q) – 16
