Advertisements
Advertisements
प्रश्न
Find out the indicated elasticity for the following function:
p = `10 e^(- x/3)`, x > 0; ηs
Advertisements
उत्तर
Given p = `10 e^(- x/3)`
Differentiating with respect to 'x' we get,
`"dp"/"dx" = 10 * e^(-x/3) (- 1/3) = - 10/3 e^(- x/3)`
`=> "dp"/"dx" = (-3)/(10e^(-x/3))`
`=> "dx"/"dp" = (-3)/(10e^(-x/3))`
Elasticity of demand
`eta_"d"= - "p"/x * "dx"/"dp"`
`=> eta_"d"= cancel(-10 e^(- x/3))/x ((-3)/(cancel(10e^(-x/3)))) = 3/x`
APPEARS IN
संबंधित प्रश्न
A firm produces x tonnes of output at a total cost of C(x) = `1/10x^3 - 4x^2 - 20x + 7` find the
- average cost
- average variable cost
- average fixed cost
- marginal cost and
- marginal average cost.
Show that MR = p`[1 - 1/eta_"d"]` for the demand function p = 400 – 2x – 3x2 where p is unit price and x is quantity demand.
For the demand function p = 550 – 3x – 6x2 where x is quantity demand and p is unit price. Show that MR =
Find the values of x, when the marginal function of y = x3 + 10x2 – 48x + 8 is twice the x.
Find the equilibrium price and equilibrium quantity for the following functions.
Demand: x = 100 – 2p and supply: x = 3p – 50.
The demand and cost functions of a firm are x = 6000 – 30p and C = 72000 + 60x respectively. Find the level of output and price at which the profit is maximum.
The cost function of a firm is C = x3 – 12x2 + 48x. Find the level of output (x > 0) at which average cost is minimum.
Find the elasticity of supply when the supply function is given by x = 2p2 + 5 at p = 1.
If demand and the cost function of a firm are p = 2 – x and C = -2x2 + 2x + 7 then its profit function is:
If the average revenue of a certain firm is ₹ 50 and its elasticity of demand is 2, then their marginal revenue is:
