Advertisements
Advertisements
प्रश्न
Find out the indicated elasticity for the following function:
p = `10 e^(- x/3)`, x > 0; ηs
Advertisements
उत्तर
Given p = `10 e^(- x/3)`
Differentiating with respect to 'x' we get,
`"dp"/"dx" = 10 * e^(-x/3) (- 1/3) = - 10/3 e^(- x/3)`
`=> "dp"/"dx" = (-3)/(10e^(-x/3))`
`=> "dx"/"dp" = (-3)/(10e^(-x/3))`
Elasticity of demand
`eta_"d"= - "p"/x * "dx"/"dp"`
`=> eta_"d"= cancel(-10 e^(- x/3))/x ((-3)/(cancel(10e^(-x/3)))) = 3/x`
APPEARS IN
संबंधित प्रश्न
A firm produces x tonnes of output at a total cost of C(x) = `1/10x^3 - 4x^2 - 20x + 7` find the
- average cost
- average variable cost
- average fixed cost
- marginal cost and
- marginal average cost.
Find the elasticity of demand in terms of x for the following demand laws and also find the value of x where elasticity is equal to unity.
p = (a – bx)2
Find the elasticity of demand in terms of x for the following demand laws and also find the value of x where elasticity is equal to unity.
p = a – bx2
Show that MR = p`[1 - 1/eta_"d"]` for the demand function p = 400 – 2x – 3x2 where p is unit price and x is quantity demand.
For the demand function p = 550 – 3x – 6x2 where x is quantity demand and p is unit price. Show that MR =
The cost function of a firm is C = x3 – 12x2 + 48x. Find the level of output (x > 0) at which average cost is minimum.
For the demand function p x = 100 - 6x2, find the marginal revenue and also show that MR = p`[1 - 1/eta_"d"]`
Average fixed cost of the cost function C(x) = 2x3 + 5x2 – 14x + 21 is:
If the average revenue of a certain firm is ₹ 50 and its elasticity of demand is 2, then their marginal revenue is:
Average cost is minimum when:
