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Find out the indicated elasticity for the following function: p = 10e-x3, x > 0; ηs

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प्रश्न

Find out the indicated elasticity for the following function:

p = `10 e^(- x/3)`, x > 0; ηs

बेरीज
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उत्तर

Given p = `10 e^(- x/3)`

Differentiating with respect to 'x' we get,

`"dp"/"dx" = 10 * e^(-x/3) (- 1/3) = - 10/3 e^(- x/3)`

`=> "dp"/"dx" = (-3)/(10e^(-x/3))`

`=> "dx"/"dp" = (-3)/(10e^(-x/3))`

Elasticity of demand

`eta_"d"= - "p"/x * "dx"/"dp"`

`=> eta_"d"= cancel(-10 e^(- x/3))/x ((-3)/(cancel(10e^(-x/3)))) = 3/x`

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Applications of Differentiation in Business and Economics
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पाठ 6: Applications of Differentiation - Miscellaneous Problems [पृष्ठ १५६]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 11 TN Board
पाठ 6 Applications of Differentiation
Miscellaneous Problems | Q 2. (ii) | पृष्ठ १५६

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