Advertisements
Advertisements
प्रश्न
Find the least square number, exactly divisible by each one of the numbers:
(i) 6, 9, 15 and 20
Advertisements
उत्तर
The smallest number divisible by 6, 9, 15 and 20 is their L.C.M., which is equal to 60.
Factorising 60 into its prime factors:
60 = 2 x 2 x 3 x 5
Grouping them into pairs of equal factors:
60 = (2 x 2) x 3 x 5
The factors 3 and 5 are not paired. To make 60 a perfect square, we have to multiply it by 3 x 5, i.e . by15.
The perfect square is 60 x 15, which is equal to 900.
APPEARS IN
संबंधित प्रश्न
Find the square root of the following number by the prime factorisation method.
5929
For the following number, find the smallest whole number by which it should be multiplied so as to get a perfect square number. Also find the square root of the square number so obtained.
252
Find the smallest number by which the given number must bew multiplied so that the product is a perfect square:
12150
Find the smallest number by which the given number must be divided so that the resulting number is a perfect square:
14283
By just examining the unit digis, can you tell which of the following cannot be whole squares?
1028
By just examining the unit digit, can you tell which of the following cannot be whole square?
1027
Find the smallest number by which 1152 must be divided so that it becomes a perfect square. Also, find the square root of the number so obtained.
A welfare association collected Rs 202500 as donation from the residents. If each paid as many rupees as there were residents, find the number of residents.
By splitting into prime factors, find the square root of 194481.
Find the smallest square number divisible by each one of the numbers 8, 9 and 10.
