Advertisements
Advertisements
प्रश्न
Find the least square number, exactly divisible by each one of the numbers:
(i) 6, 9, 15 and 20
Advertisements
उत्तर
The smallest number divisible by 6, 9, 15 and 20 is their L.C.M., which is equal to 60.
Factorising 60 into its prime factors:
60 = 2 x 2 x 3 x 5
Grouping them into pairs of equal factors:
60 = (2 x 2) x 3 x 5
The factors 3 and 5 are not paired. To make 60 a perfect square, we have to multiply it by 3 x 5, i.e . by15.
The perfect square is 60 x 15, which is equal to 900.
APPEARS IN
संबंधित प्रश्न
For the following number, find the smallest whole number by which it should be multiplied so as to get a perfect square number. Also find the square root of the square number so obtained.
2028
For the following number, find the smallest whole number by which it should be divided so as to get a perfect square number. Also find the square root of the square number so obtained.
396
Find the smallest square number that is divisible by each of the numbers 8, 15, and 20.
Write true (T) or false (F) for the following statement.
The square of a prime number is prime.
Write true (T) or false (F) for the following statement.
No square number is negative.
Find the square root the following by prime factorization.
8281
The product of two numbers is 1296. If one number is 16 times the other, find the numbers.
Find the smallest number by which 2592 be multiplied so that the product is a perfect square.
Find the smallest number by which 12748 be mutliplied so that the product is a perfect square?
Find the smallest perfect square divisible by 3, 4, 5 and 6.
