Advertisements
Advertisements
प्रश्न
Find the least square number, exactly divisible by each one of the number:
8, 12, 15 and 20
Advertisements
उत्तर
The smallest number divisible by 8, 12, 15 and 20 is their L.C.M., which is equal to 120.
Factorising 120 into its prime factors:
120 = 2 x 2 x 2 x 3 x 5
Grouping them into pairs of equal factors:
120 = (2 x 2) x 2 x 3 x 5
The factors 2, 3 and 5 are not paired. To make 120 into a perfect square, we have to multiply it by 2 x 3 x 5, i.e. by 30.
The perfect square is 120 x 30, which is equal to 3600.
APPEARS IN
संबंधित प्रश्न
Find the smallest square number that is divisible by each of the numbers 4, 9, and 10.
By just examining the unit digit, can you tell which of the following cannot be whole square?
1027
Find the squares of the following numbers using column method. Verify the result by finding the square using the usual multiplication:
25
Find the square root the following by prime factorization.
529
Find the square root the following by prime factorization.
1156
Find the square root the following by prime factorization.
586756
A welfare association collected Rs 202500 as donation from the residents. If each paid as many rupees as there were residents, find the number of residents.
Find the smallest number by which 12748 be mutliplied so that the product is a perfect square?
Find the smallest perfect square divisible by 3, 4, 5 and 6.
Find the square root by prime factorisation method
144
