Advertisements
Advertisements
प्रश्न
Find the least square number, exactly divisible by each one of the numbers:
(i) 6, 9, 15 and 20
Advertisements
उत्तर
The smallest number divisible by 6, 9, 15 and 20 is their L.C.M., which is equal to 60.
Factorising 60 into its prime factors:
60 = 2 x 2 x 3 x 5
Grouping them into pairs of equal factors:
60 = (2 x 2) x 3 x 5
The factors 3 and 5 are not paired. To make 60 a perfect square, we have to multiply it by 3 x 5, i.e . by15.
The perfect square is 60 x 15, which is equal to 900.
APPEARS IN
संबंधित प्रश्न
Find the square root of the following number by the prime factorisation method.
1764
Find the square root of the following number by the prime factorisation method.
9216
For the following number, find the smallest whole number by which it should be multiplied so as to get a perfect square number. Also find the square root of the square number so obtained.
2028
For the following number, find the smallest whole number by which it should be divided so as to get a perfect square number. Also find the square root of the square number so obtained.
252
For the following number, find the smallest whole number by which it should be divided so as to get a perfect square number. Also find the square root of the square number so obtained.
2800
By just examining the unit digit, can you tell which of the following cannot be whole square?
1024
Write five numbers which you cannot decide whether they are square just by looking at the unit's digit.
Find the square root the following by prime factorization.
3013696
Out of 745 students, maximum are to be arranged in the school field for a P.T. display, such that the number of rows is equal to the number of columns. Find the number of rows if 16 students were left out after the arrangement.
Find the smallest perfect square divisible by 3, 4, 5 and 6.
