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Find k if following function is continuous at the point indicated against them: f(x) =(5x-88-3x)12x-4,for x≠2=k,for x=2} at x = 2

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प्रश्न

Find k if following function is continuous at the point indicated against them:

f(x) `{:(= ((5x - 8)/(8 - 3x))^(3/(2x - 4))",", "for"  x ≠ 2),(= "k"",", "for"  x = 2):}}` at x = 2

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उत्तर

f(x) is continuous at x = 2

∴ f(2) = `lim_(x -> 2) "f"(x)`

∴ k = `lim_(x -> 2) ((5x - 8)/(8 - 3x))^(3/(2x - 4))`

Put x – 2 = h

∴ x = 2 + h

As x → 2, h → 0

∴ k = `lim_("h" -> 0) [(5(2 + "h") - 8)/(8 - 3(2 + "h"))]^(3/(2"h"))`

= `lim_("h" -> 0) ((10 + 5"h" - 8)/(8 - 6 - 3"h"))^(3/(2"h"))`

= `lim_("h" -> 0) ((2 + 5"h")/(2 - 3"h"))^(3/(2"h"))`

= `lim_("h" -> 0) [(2(1 + (5"h")/2))/(2(1 - (3"h")/2))]^(3/(2"h"))`

= `lim_("h" -> 0) (1 + (5"h")/2)^(3/(2"h"))/((1 - (3"h")/2)^(3/(2"h"))`

= `(lim_("h" -> 0) [(1 + (5"h")/2)^(2/(5"h"))]^(5/2 xx 3/2))/(lim_("h" -> 0)[(1 - (3"h")/2)^((-2)/(3"h"))]^((-3)/2 xx 3/2)`

= `"e"^(15/4)/"e"^((-9)/4)   ...[(because "h" -> 0","  (5"h")/2 -> 0","  (-3"h")/2 -> 0),("and" lim_(x -> 0) (1 + x)^(1/x) =  "e")]`

= `"e"^(24/4)`

= e6

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Continuity - MISCELLANEOUS EXERCISE-8 [पृष्ठ १७८]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 8 Continuity
MISCELLANEOUS EXERCISE-8 | Q (V) (1) | पृष्ठ १७८

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