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Solve using intermediate value theorem: Show that 5x − 6x = 0 has a root in [1, 2]

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प्रश्न

Solve using intermediate value theorem:

Show that 5x − 6x = 0 has a root in [1, 2]

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उत्तर

Let f(x) = 5x − 6x

5x and 6x are continuous functins for all x ∈ R.

∴ 5x − 6x is also continuous for all x ∈ R.

i.e. f(x) is continuous for all x ∈ R.

A root of f(x) exists if f(x) = 0 for at least one value of x.

f(1) = 51 − 6 (1)

= − 1 < 0

f(2) = (5)2 − 6 (2)

= 13 > 0

∴ f(1) < 0 and f(2) > 0

By intermediate value theorem, there has to be a point ‘c’ between 1 and 2 such that f(c) = 0.

∴ There is a root of the given equation in [1, 2].

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अध्याय 8: Continuity - MISCELLANEOUS EXERCISE-8 [पृष्ठ १७८]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 8 Continuity
MISCELLANEOUS EXERCISE-8 | Q (VIII) (1) | पृष्ठ १७८

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