Advertisements
Advertisements
प्रश्न
Find the following product:
(4x − 3y + 2z) (16x2 + 9y2 + 4z2 + 12xy + 6yz − 8zx)
Advertisements
उत्तर
In the given problem, we have to find Product of equations
Given (4x − 3y + 2z) (16x2 + 9y2 + 4z2 + 12xy + 6yz − 8zx)
We shall use the identity
`x^3 + y^3 + z^3 - 3xyz = (x+ y +z)(x^2 + y^2 + z^2 - xy - yz - zx)`
` = (4x)^3 + (3y)^3 + (2z)^3 -3 (4x)(3y)(2z)`
` = (4x) xx (4x) xx (4x) +(-3y) xx (-3y) xx (-3y) + (2z) xx (2z) xx (2z) -3 (4x) (-3y)(2z)`
` = 64x^3 - 27y^3 + 8z^3 + 72 xyz`
Hence the product of (4x − 3y + 2z) (16x2 + 9y2 + 4z2 + 12xy + 6yz − 8zx) is `64x^2 - 27y^3 + 8z^3 + 72xyz`
APPEARS IN
संबंधित प्रश्न
Use suitable identity to find the following product:
(3x + 4) (3x – 5)
Write the following cube in expanded form:
`[3/2x+1]^3`
Evaluate following using identities:
(a - 0.1) (a + 0.1)
Write in the expanded form:
`(m + 2n - 5p)^2`
If a2 + b2 + c2 = 16 and ab + bc + ca = 10, find the value of a + b + c.
Find the cube of the following binomials expression :
\[4 - \frac{1}{3x}\]
Find the value of 27x3 + 8y3, if 3x + 2y = 14 and xy = 8
If `x^4 + 1/x^4 = 194, "find" x^3 + 1/x^3`
Find the following product:
If \[x^2 + \frac{1}{x^2} = 102\], then \[x - \frac{1}{x}\] =
If \[x - \frac{1}{x} = \frac{15}{4}\], then \[x + \frac{1}{x}\] =
Use identities to evaluate : (101)2
Evaluate `(a/[2b] + [2b]/a )^2 - ( a/[2b] - [2b]/a)^2 - 4`.
If 3x + 4y = 16 and xy = 4, find the value of 9x2 + 16y2.
Use the direct method to evaluate :
(2a+3) (2a−3)
Evaluate: (2a + 0.5) (7a − 0.3)
Evaluate: (9 − y) (7 + y)
Evaluate, using (a + b)(a - b)= a2 - b2.
999 x 1001
The value of 2492 – 2482 is ______.
Give possible expressions for the length and breadth of the rectangle whose area is given by 4a2 + 4a – 3.
