Advertisements
Advertisements
प्रश्न
Evaluate following using identities:
(a - 0.1) (a + 0.1)
Advertisements
उत्तर
In the given problem, we have to evaluate expressions by using identities.
The given expression is (a + 0.1)(a - 0.1)
We shall use the identity `(x + y)(x - y) = x^2 - y^2`
Here x = a
y = 0.1
By applying identity we get
`(a + 0.1)(a - 0.1) = (a)^2 - (0.1)^2`
`= (a xx a) - (0.1 xx 0.1)`
`= a^2 - 0.01`
Hence the value of (a + 0.1)(a - 0.1) is `a^2 - 0.01`
APPEARS IN
संबंधित प्रश्न
Write the following cube in expanded form:
`[3/2x+1]^3`
Factorise the following:
64a3 – 27b3 – 144a2b + 108ab2
Without actually calculating the cubes, find the value of the following:
(28)3 + (–15)3 + (–13)3
Simplify the following expressions:
`(x^2 - x + 1)^2 - (x^2 + x + 1)^2`
If a − b = 4 and ab = 21, find the value of a3 −b3
Evaluate of the following:
(9.9)3
Find the value of 27x3 + 8y3, if 3x + 2y = 20 and xy = \[\frac{14}{9}\]
Simplify of the following:
(x+3)3 + (x−3)3
Find the following product:
(4x − 5y) (16x2 + 20xy + 25y2)
If x = 3 and y = − 1, find the values of the following using in identify:
\[\left( \frac{3}{x} - \frac{x}{3} \right) \left( \frac{x^2}{9} + \frac{9}{x^2} + 1 \right)\]
Find the following product:
(3x − 4y + 5z) (9x2 +16y2 + 25z2 + 12xy −15zx + 20yz)
Use identities to evaluate : (998)2
Use the direct method to evaluate the following products:
(5a + 16) (3a – 7)
Find the squares of the following:
(2a + 3b - 4c)
If x + y = 9, xy = 20
find: x - y
If a2 + b2 + c2 = 41 and a + b + c = 9; find ab + bc + ca.
If `"p" + (1)/"p" = 6`; find : `"p"^2 + (1)/"p"^2`
Simplify:
(7a +5b)2 - (7a - 5b)2
Simplify:
(3a + 2b - c)(9a2 + 4b2 + c2 - 6ab + 2bc +3ca)
If a + b + c = 9 and ab + bc + ca = 26, find a2 + b2 + c2.
