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Find dy/dx in the following: ax + by2 = cos y - Mathematics

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प्रश्न

Find `bb(dy/dx)` in the following:

ax + by2 = cos y

योग
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उत्तर

ax + by2 = cos y

Differentiating both sides with respect to x,

⇒ `a d/dx (x) + b d/dx (y^2) = d/dx(cos y)`

⇒ `a xx 1 + b * 2y dy/dx = - sin y dy/dx`

⇒ `a + 2by dy/dx + sin y dy/dx = 0`

⇒ `a + dy/dx (2by +sin y) = 0`

⇒ `dy/dx (2by + sin y) = - a`

∴ `dy/dx = (-a)/(2by + sin y)`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Continuity and Differentiability - Exercise 5.3 [पृष्ठ १६९]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 5 Continuity and Differentiability
Exercise 5.3 | Q 3 | पृष्ठ १६९

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