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प्रश्न
Find the domain of the real valued function of real variable:
(iii) \[f\left( x \right) = \sqrt{9 - x^2}\]
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उत्तर
(iii) Given:
\[f\left( x \right) = \sqrt{9 - x^2}\]
We observe that f (x) is defined for all satisfying
9 -x2 ≥ 0 .
⇒ x2 -9 ≤ 0
⇒ (x + 3)(x -3) ≤ 0
⇒-3 ≤ x ≤ 3
x ∈ [ -3, 3]
Hence, domain ( f ) = [-3, 3]
9 -x2 ≥ 0 .
⇒ x2 -9 ≤ 0
⇒ (x + 3)(x -3) ≤ 0
⇒-3 ≤ x ≤ 3
x ∈ [ -3, 3]
Hence, domain ( f ) = [-3, 3]
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