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प्रश्न
Find the domain of the real valued function of real variable:
(iii) \[f\left( x \right) = \frac{3x - 2}{x + 1}\]
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उत्तर
(iii) Given:
\[f\left( x \right) = \frac{3x - 2}{\left( x + 1 \right)}\]
Domain of f :
Clearly, f (x) is not defined for all (x + 1) = 0, i.e. x = - 1.
At x = -1, f (x) takes the intermediate form \[\frac{1}{0} .\]
Clearly, f (x) is not defined for all (x + 1) = 0, i.e. x = - 1.
At x = -1, f (x) takes the intermediate form \[\frac{1}{0} .\]
Hence, domain ( f ) = R - { - 1 }.
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