हिंदी

Find ∣ ∣ → a − → B ∣ ∣ | → a | = 3 , ∣ ∣ → B ∣ ∣ = 4 and → a ⋅ → B = 1

Advertisements
Advertisements

प्रश्न

Find \[\left| \vec{a} - \vec{b} \right|\]  

\[\left| \vec{a} \right| = 3, \left| \vec{b} \right| = 4 \text{ and } \vec{a} \cdot \vec{b} = 1\] 

योग
Advertisements

उत्तर

\[\text{ Given that }\]

\[\left| \vec{a} \right| = 3, \left| \vec{b} \right| = 4 \text{ and } \vec{a} . \vec{b} = 1.................. \left( 1 \right)\]

\[\text{ We know that }\]

\[ \left| \vec{a} - \vec{b} \right|^2 = \left| \vec{a} \right|^2 + \left| \vec{b} \right|^2 - 2 \vec{a} . \vec{b} \]

\[ = 3^2 + 4^2 - 2 \left( 1 \right)............... \left[ \text{ Using } \left( 1 \right) \right]\]

\[ = 9 + 16 - 2\]

\[ = 23\]

\[ \therefore \left| \vec{a} - \vec{b} \right| = \sqrt{23}\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 23: Scalar Or Dot Product - Exercise 24.1 [पृष्ठ ३१]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 23 Scalar Or Dot Product
Exercise 24.1 | Q 32.2 | पृष्ठ ३१
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×