हिंदी

Find the Area of the Circle 4x2 + 4y2 = 9 Which is Interior to the Parabola X2 = 4y - Mathematics

Advertisements
Advertisements

प्रश्न

Find the area of the circle 4x2 + 4y2 = 9 which is interior to the parabola x2 = 4y

Advertisements

उत्तर

The required area is represented by the shaded area OBCDO.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Application of Integrals - Exercise 8.2 [पृष्ठ ३७१]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 8 Application of Integrals
Exercise 8.2 | Q 1 | पृष्ठ ३७१

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Using integration, find the area of the region bounded by the triangle whose vertices are (−1, 2), (1, 5) and (3, 4).


Find the area of the region lying between the parabolas y2 = 4ax and x2 = 4ay.


Find the area bounded by curves (x – 1)2 + y2 = 1 and x2 + y 2 = 1


Using integration finds the area of the region bounded by the triangle whose vertices are (–1, 0), (1, 3) and (3, 2).


Smaller area enclosed by the circle x2 + y2 = 4 and the line x + y = 2 is

A. 2 (π – 2)

B. π – 2

C. 2π – 1

D. 2 (π + 2)


Using the method of integration find the area bounded by the curve |x| + |y| = 1 .

[Hint: The required region is bounded by lines x + y = 1, x– y = 1, – x + y = 1 and
– x – y = 1].


Find the area bounded by curves {(x, y) : y ≥ x2 and y = |x|}.


Choose the correct answer The area of the circle x2 + y2 = 16 exterior to the parabola y2 = 6x is

A. `4/3 (4pi - sqrt3)`

B. `4/3 (4pi + sqrt3)`

C. `4/3 (8pi - sqrt3)`

D.`4/3 (4pi + sqrt3)`


The area bounded by the y-axis, y = cos x and y = sin x when  0 <= x <= `pi/2`

(A) 2 ( 2 −1)

(B) `sqrt2 -1`

(C) `sqrt2 + 1`

D. `sqrt2`


Using integration, find the area of region bounded by the triangle whose vertices are (–2, 1), (0, 4) and (2, 3).


Show that the rectangle of the maximum perimeter which can be inscribed in the circle of radius 10 cm is a square of side `10sqrt2` cm.


Find the area included between the parabolas y2 = 4ax and x2 = 4by.


The area enclosed between the curves y = loge (x + e), x = log\[\left( \frac{1}{y} \right)\] and the x-axis is _______ .


The area between x-axis and curve y = cos x when 0 ≤ x ≤ 2 π is ___________ .


Area lying between the curves y2 = 4x and y = 2x is


Solve the following :

Find the area of the region lying between the parabolas y2 = 4x and x2 = 4y.


The area enclosed between the two parabolas y2 = 20x and y = 2x is ______ sq.units


Find the area enclosed between y = cos x and X-axis between the lines x = `pi/2` and x ≤ `(3pi)/2`


Find the area of the ellipse `x^2/1 + y^2/4` = 1, in first quadrant


Find the area enclosed between the X-axis and the curve y = sin x for values of x between 0 to 2π


Find the area of the region lying between the parabolas 4y2 = 9x and 3x2 = 16y


Find the area of the region included between y = x2 + 5 and the line y = x + 7


Find the area enclosed between the circle x2 + y2 = 9, along X-axis and the line x = y, lying in the first quadrant


Find the area of the region included between the parabola y = `(3x^2)/4` and the line 3x – 2y + 12 = 0.


Find the area of the region bounded by the curves x = at2 and y = 2at between the ordinate corresponding to t = 1 and t = 2.


Calcualte the area under the curve y = `2sqrt(x)` included between the lines x = 0 and x = 1


Determine the area under the curve y = `sqrt("a"^2 - x^2)` included between the lines x = 0 and x = a.


Area lying between the curves `y^2 = 4x` and `y = 2x`


Using Integration, find the area of triangle whose vertices are (– 1, 1), (0, 5) and (3, 2).


Find the area enclosed between 3y = x2, X-axis and x = 2 to x = 3.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×