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Find the Acceleration of a Particle Placed on the Surface of the Earth at the Equator Due to Earth'S Rotation. the Diameter of Earth = 12800 Km

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प्रश्न

Find the acceleration of a particle placed on the surface of the earth at the equator due to earth's rotation. The diameter of earth = 12800 km and it takes 24 hours for the earth to complete one revolution about its axis.

योग
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उत्तर

Diameter of the Earth = 12800 km
So, radius of the Earth, R = 6400 km = 6.4 × 106

Time period of revolution of the Earth about its axis :

\[T = 24 \text{hr} = 24 \times 3600 \text{s}\]

\[\text{v} = \frac{2\pi r}{T}=\frac{2 \times 3 . 14 \times 64 \times {10}^6}{24 \times 3600}\]

\[\Rightarrow \text{v} = 465 . 185 \text{ m/s}\]

\[\text { Acceleration of the particle }: \]

\[a = \frac{v^2}{R} = \frac{\left( 465 . 185 \right)^2}{64 \times {10}^5} = 0 . 038 \text{ m/ s}^2\]

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अध्याय 7: Circular Motion - Exercise [पृष्ठ ११४]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 7 Circular Motion
Exercise | Q 2 | पृष्ठ ११४

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