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प्रश्न
Find a vector of magnitude 9 units and perpendicular to the vectors.
`veca = 4hati - hatj + hatk` and `vecb = -2hati + hatj - 2hatk`
योग
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उत्तर
A vector of magnitude 9 units and perpendicular to the vectors `veca` and `vecb` is `9((veca xx vecb)/(|veca xx vecb|))`
Given, `veca = 4hati - hatj + hatk` and `vecb = -2hati + hatj - 2hatk`
`veca xx vecb = |(hati, hatj, hatk),(4, -1, 1),(-2, 1, -2)|`
= `hati + 6hatj + 2hatk` and `|veca xx vecb| = sqrt(41)`
Hence required vector is `9/sqrt(41)(hati + 6hatj + 2hatk)`
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Magnitude and Direction of a Vector
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