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प्रश्न
Figure shows the stopping potential (V0) for the photo electron versus (1/λ) graph, for two metals A and B, λ being the wavelength of incident light.

- How is the value of Planck’s constant determined from the graph?
- If the distance between the light source and the surface of metal A is increased, how will the stopping potential for the electrons emitted from it be effected? Justify your answer.
औचित्य
दीर्घउत्तर
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उत्तर
a. Planck’s constant can be determined from the gradient of the graph.
Gradient = `(h c)/e`
h = Planck’s constant
c = Velocity of light in vacuum
e = Charge of electron
The gradient is to be measured from the graph. The values of c and e are known. Hence, h can be determined.
b. As the distance between the light source and the surface of metal A increases, the intensity of the incident light diminishes. However, the stopping potential is independent of the intensity of the incident light. The stopping potential will remain unaffected.
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