Advertisements
Advertisements
प्रश्न
Factorize the following expressions:
x3 + 6x2 +12x +16
Advertisements
उत्तर
= x3 + 6x2 +12x + 8 + 8
= x3 + 3 × x2 × 2 + 3 × x × 22 + 23 + 8
= ( x = 2)3 + 8 [ ∵ a3 + 3a2b + 3ab2 + b3 = (a + b)3]
= ( x + 2)3 + 23
= ( x + 2 + 2)(( x + 2)2 - 2 ( x + 2) + 22 ) [∵ a3 + b3 = (a + b)(a2 - ab + b2 ) ]
= ( x + 4)(x2 + 4x + 4 - 2x - 4 + 4) [∵ (a + b)2 = a2 + 2ab + b2]
= ( x + 4)(x2 + 2x + 4)
∴ x3 + 6x2 +12x +16 = ( x + 4)(x2 + 2x + 4)
APPEARS IN
संबंधित प्रश्न
Get the algebraic expression in the following case using variables, constants and arithmetic operations.
Number 5 added to three times the product of numbers m and n.
Factorize (a - b + c)2 + (b - c + a)2 + 2(a - b + c) (b - c + a)
Factorize x4 + x2 y2 + y4
Factorize `2x^2 - 5/6x + 1/12`
What are the possible expressions for the dimensions of the cuboid whose volume is 3x2 - 12x.
Write the number of the term of the following polynomial.
ax ÷ 4 – 7
Write the number of the term of the following polynomial.
23 + a x b ÷ 2
Divide: 8m - 16 by - 8
Which of the following expressions has the value 37?
Write the variables, constant and terms of the following expression
29x + 13y
