Advertisements
Advertisements
प्रश्न
Factorise the following:
(a + b)2 + 9(a + b) + 18
Advertisements
उत्तर
Let (a + b) = x
x2 + 9x + 18
Product = 18, sum = 9

Split the middle term as 6x and 3x
x2 + 9x + 18 = x2 + 6x + 3x + 18
= x(x + 6) + 3(x + 6)
= (x + 6)(x + 3)
But x = a + b
(a + b)2 + 9(a + b) + 18 = (a + b + 6)(a + b + 3)
APPEARS IN
संबंधित प्रश्न
Identify polynomials in the following:
`g(x)=2x^3-3x^2+sqrtx-1`
f(x) = 9x3 − 3x2 + x − 5, g(x) = \[x - \frac{2}{3}\]
If the polynomials 2x3 + ax2 + 3x − 5 and x3 + x2 − 4x +a leave the same remainder when divided by x −2, find the value of a.
f(x) = x3 − 6x2 + 11x − 6, g(x) = x2 − 3x + 2
Find the value of a, if x + 2 is a factor of 4x4 + 2x3 − 3x2 + 8x + 5a.
x3 − 2x2 − x + 2
Let f(x) be a polynomial such that \[f\left( - \frac{1}{2} \right)\] = 0, then a factor of f(x) is
If (3x − 1)7 = a7x7 + a6x6 + a5x5 +...+ a1x + a0, then a7 + a5 + ...+a1 + a0 =
Factorise the following:
5x2 – 29xy – 42y2
Factorise:
x3 + x2 – 4x – 4
