Advertisements
Advertisements
प्रश्न
Factorise the following:
27y3 + 125z3
Advertisements
उत्तर
We know that = (x + y) (x2 + y2 − xy) = x3 + y3
It is given that = 27y3 + 125z3 = (3y)3 + (5z)3
= (3y + 5z) [(3y)2 − (3y)(5z) + (5z)2]
= (3y + 5z) (9y2 − 15yz + 25z2)
APPEARS IN
संबंधित प्रश्न
Verify that `x^3+y^3+z^3-3xyz=1/2(x+y+z)[(x-y)^2+(y-z)^2+(z-x)^2]`
Evaluate following using identities:
(a - 0.1) (a + 0.1)
Evaluate following using identities:
991 ☓ 1009
Simplify the following
`(7.83 + 7.83 - 1.17 xx 1.17)/6.66`
Simplify the following product:
(x2 + x − 2)(x2 − x + 2)
Simplify the following products:
`(x^3 - 3x^2 - x)(x^2 - 3x + 1)`
Find the cube of the following binomials expression :
\[2x + \frac{3}{x}\]
If \[x - \frac{1}{x} = 5\], find the value of \[x^3 - \frac{1}{x^3}\]
Evaluate of the following:
(9.9)3
Find the following product:
\[\left( \frac{3}{x} - \frac{5}{y} \right) \left( \frac{9}{x^2} + \frac{25}{y^2} + \frac{15}{xy} \right)\]
Use the direct method to evaluate the following products :
(3x – 2y) (2x + y)
Use the direct method to evaluate :
(0.5−2a) (0.5+2a)
Evaluate: (5xy − 7) (7xy + 9)
Evaluate the following without multiplying:
(1005)2
If `x + (1)/x = 3`; find `x^2 + (1)/x^2`
If `"a"^2 + (1)/"a"^2 = 14`; find the value of `"a" + (1)/"a"`
If `x + (1)/x = "p", x - (1)/x = "q"`; find the relation between p and q.
Simplify:
(2x + y)(4x2 - 2xy + y2)
Factorise the following:
4x2 + 20x + 25
