Advertisements
Advertisements
प्रश्न
Factorise the following:
27 – 125a3 – 135a + 225a2
Advertisements
उत्तर
27 – 125a3 – 135a + 225a2
= 33 – (5a)3 – 3(3) (5a) (3 – 5a)
= (3 – 5a)3 ...[Using a3 − b3 − 3ab(a − b) = (a − b)3]
= (3 – 5a)(3 – 5a)(3 – 5a)
APPEARS IN
संबंधित प्रश्न
Expand the following, using suitable identity:
(2x – y + z)2
Expand the following, using suitable identity:
(3a – 7b – c)2
Factorise:
`2x^2 + y^2 + 8z^2 - 2sqrt2xy + 4sqrt2yz - 8xz`
Write the following cube in expanded form:
(2a – 3b)3
Factorise the following:
`27p^3-1/216-9/2p^2+1/4p`
Write in the expanded form: `(x + 2y + 4z)^2`
Write in the expanded form: (-2x + 3y + 2z)2
Find the cube of the following binomials expression :
\[4 - \frac{1}{3x}\]
If a + b = 10 and ab = 21, find the value of a3 + b3
Evaluate of the following:
`(10.4)^3`
Evaluate of the following:
(598)3
Find the following product:
Find the following product:
If a + `1/a`= 6 and a ≠ 0 find :
(i) `a - 1/a (ii) a^2 - 1/a^2`
Expand the following:
`(2"a" + 1/(2"a"))^2`
Evaluate the following without multiplying:
(1005)2
If `"a" - 1/"a" = 10`; find `"a"^2 - 1/"a"^2`
If m - n = 0.9 and mn = 0.36, find:
m2 - n2.
If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a"^2 - (1)/"a"^2`
