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प्रश्न
Factorise:
a6 – b6
योग
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उत्तर
We know that,
a3 + b3 = (a + b) (a2 – ab + b2) ...(1)
a3 – b3 = (a – b) (a2 + ab + b2) ...(2)
a6 – b6 = (a3)2 – (b3)2
= (a3 + b3) (a3 – b3)
= (a + b) (a2 – ab + b2) (a – b) (a2 + ab + b2)
[From (1) and (2)]
= (a + b) (a – b) (a2 – ab + b2) (a2 + ab + b2)
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Method of Factorisation : the Sum Or Difference of Two Cubes
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Factorise : 64 - a3b3
Factorise : a6 + 27b3
Factorise : a3 + 0.064
Factorise : a3 + 0.064
Factorise : a3 + 0.064
Factorise:
`(8"a"^3)/27 - "b"^3/8`
Factorise : 2x3 + 54y3 - 4x - 12y
Show that : 133 - 53 is divisible by 8
Show that : 353 + 273 is divisible by 62
Factorise:
a3 - 27b3 + 2a2b - 6ab2
