Advertisements
Advertisements
प्रश्न
Factorise:
a6 – b6
योग
Advertisements
उत्तर
We know that,
a3 + b3 = (a + b) (a2 – ab + b2) ...(1)
a3 – b3 = (a – b) (a2 + ab + b2) ...(2)
a6 – b6 = (a3)2 – (b3)2
= (a3 + b3) (a3 – b3)
= (a + b) (a2 – ab + b2) (a – b) (a2 + ab + b2)
[From (1) and (2)]
= (a + b) (a – b) (a2 – ab + b2) (a2 + ab + b2)
shaalaa.com
Method of Factorisation : the Sum Or Difference of Two Cubes
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Factorise:
a3 - 27
Factorise : 3x7y - 81x4y4
Factorise : a3 - `27/a^3`
Factorise: (x - y)3 - 8x3
Factorise : 1029 - 3x3
Show that : 353 + 273 is divisible by 62
Factorise:
a3 - 27b3 + 2a2b - 6ab2
Factorise : 8a3 - b3 - 4ax + 2bx
Factorise : a - b - a3 + b3
Evaluate :
`[ 5.67 xx 5.67 xx 5.67 + 4.33 xx 4.33 xx 4.33 ]/[5.67 xx 5.67 - 5.67 xx 4.33 + 4.33 xx 4.33]`
