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प्रश्न
Factorise : 1 - 8a3
योग
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उत्तर
1 - 8a3
= (1)3 - (2a)3
= ( 1 - 2a )[ (1)2 + 1 x 2a + (2a)2 ]
[ ∵ a3 - b3 = ( a - b )( a2 + ab + b2 )]
= ( 1 - 2a )[ 1 + 2a + 4a2 ]
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Method of Factorisation : the Sum Or Difference of Two Cubes
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