Advertisements
Advertisements
प्रश्न
Factorise : a2 - b2 - (a + b) 2
योग
Advertisements
उत्तर
a2 - b2 - (a + b) 2
= a2 - b2 - ( a2 + 2ab + b2 )
= a2 - b2 - a2 - 2ab - b2
= - 2ab - 2b2
= - 2b( a + b )
shaalaa.com
Method of Factorisation : Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise : 25a2 - 9b2
Factorise : a2 - 81 (b-c)2
Factorise : a4 - 1
Factorise : 9a2 + 3a - 8b - 64b2
Factorise:
(a2 − 1) (b2 − 1) + 4ab
Factorize : 9a2 - (a2 - 4) 2
Factorise : a2 ( b + c) - (b + c)3
Factorise the following by the difference of two squares:
441 - 81y2
Factorise the following:
(2a - b)2 -9(3c - d)2
Factorise the following:
y4 + y2 + 1
