Advertisements
Advertisements
प्रश्न
Factorize : 9a2 - (a2 - 4) 2
योग
Advertisements
उत्तर
9a2 - (a2 - 4)2
= (3a)2 - (a2 - 4)2
= [ 3a + (a2 - 4)][ 3a - (a2 - 4)]
= [ 3a + a2 - 4 ][ 3a - a2 + 4 ]
= [ a2 + 3a - 4 ][- a2 + 3a + 4]
= (a + 4)(a - 1)(-a2 + 3a + 4)
= (a + 4)(a - 1)[-(a2 - 3a - 4)]
= - (a + 4)(a - 1)(a - 4)(a + 1)
= (a + 4)(a - 1)(a + 1)(4 - a).
shaalaa.com
Method of Factorisation : Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise: 4a2 - (4b2 + 4bc + c2)
Factorise : 4a2 - 12a + 9 - 49b2
Factorise : 4x2 - 12ax - y2 - z2 - 2yz + 9a2
Factorise : (a2 + b2 - 4c2)2 - 4a2b2
Factorise : (a + b) 2 - a2 + b2
Factorise the following by the difference of two squares:
x6 - 196
Factorise the following by the difference of two squares:
a(a - 1) - b(b - 1)
Factorise the following:
9(a - b)2 - (a + b)2
Factorise the following:
25(x - y)2 - 49(c - d)2
Factorise the following:
4xy - x2 - 4y2 + z2
