Advertisements
Advertisements
प्रश्न
Factorize : 9a2 - (a2 - 4) 2
Advertisements
उत्तर
9a2 - (a2 - 4)2
= (3a)2 - (a2 - 4)2
= [ 3a + (a2 - 4)][ 3a - (a2 - 4)]
= [ 3a + a2 - 4 ][ 3a - a2 + 4 ]
= [ a2 + 3a - 4 ][- a2 + 3a + 4]
= (a + 4)(a - 1)(-a2 + 3a + 4)
= (a + 4)(a - 1)[-(a2 - 3a - 4)]
= - (a + 4)(a - 1)(a - 4)(a + 1)
= (a + 4)(a - 1)(a + 1)(4 - a).
APPEARS IN
संबंधित प्रश्न
Factorise : 50a3 - 2a
Factorise : a4 - 1
Factorise : a2 + b2 - c2 - d2 + 2ab - 2cd
Factorise : `4x^2 + 1/(4x)^2 + 1`
Factorise : a2 ( b + c) - (b + c)3
Factorise the following by the difference of two squares:
(x - 2y)2 -z2
Factorise the following:
b2 - 2bc + c2 - a2
Factorise the following:
(a2 – b2)(c2 – d2) – 4abcd
Express each of the following as the difference of two squares:
(x2 - 2x + 3)(x2 + 2x + 3)
Express each of the following as the difference of two squares:
(x2 + 2x - 3) (x2 - 2x + 3)
