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प्रश्न
Factorise: a2 - b2 - 2b - 1
योग
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उत्तर
a2 - b2 - 2b - 1
= a2 - (b2 + 2b + 1)
...[(a + b)2 = a2 + b2 + 2ab]
...[a2 - b2 = (a + b) (a - b)]
= (a)2 - (b + 1)2
= (a + b + 1)(a - b - 1)
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Factorisation by Difference of Two Squares
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