Advertisements
Advertisements
प्रश्न
Factorise: 4(2a + b)2 - (a - b)2
योग
Advertisements
उत्तर
4(2a + b)2 - (a - b)2
= [2(2a + b)]2 - (a - b)2
= [2(2a + b) + a - b][2 (2a + b) -a + b]
= (4a + 2b + a - b)(4a + 2b - a + b)
= (5a + b)(3a + 3b)
= (5a + b) 3(a + b)
= 3 (5a + b) (a + b)
shaalaa.com
Factorisation by Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise: 16 - 9x2
Factorise: 1 - 25 (a+ b)2
Factorise: `(7 3/10)^2 - (2 1/10)^2`
Factorise: (0·7)2 - (0·3)2
Factorise: 75(x + y)2 - 48(x - y)2
factorise : 25(2x - y)2 - 16(x - 2y)2
Factorise: 25(a - 5b)2 - 4(a - 3b)2
Factorise: 15(2x - y)2 - 16(2x - y) - 15
Factorise a2b − b3. Using this result, find the value of 1012 × 100 − 1003.
Evaluate (using factors) : 3012 x 300 - 3003.
